I apologize for any confusion earlier. However, based on the given information and triangle conditions, the accurate numerical value of angle BDA is indeed 15 degrees. If you are certain that the correct answer is 45 degrees, there might be an issue or misunderstanding with the given conditions or the problem statement. 0170以下、5ちゃんねるからVIPがお送りします2023/08/12(土) 02:04:57.031ID:yNqJGib30>>169 これ先生に提出すれば正解なのかね 0171以下、5ちゃんねるからVIPがお送りします2023/08/12(土) 02:08:21.667ID:D3HYYQQU0>>169 これも間違っていて、 ここがミスってる Angle ABD + Angle BAD + Angle BDA = 180 degrees 30 + 135 + Angle BDA = 180 0172以下、5ちゃんねるからVIPがお送りします2023/08/12(土) 02:11:33.428ID:D3HYYQQU0 Googleのbardのほうは調教したら以下を吐いたよ。 Imagine triangle ABC. given point D on line BC at BD=DC. angle ABD = angle ABC = 30 degrees, angle ACD = angle ACB = 15 degrees . re-olve angle BDA in numeric (in degree). 他の回答案を表示
Solution: 1. The sum of the angles in a triangle is 180 degrees. 2. Therefore, angle BDA = 180 - angle ABD - angle ABC - angle ACD - angle ACB 3. Since BD = DC, triangle ABD is isosceles, so angle ABD = angle ADB. 4. Since angle ABD = angle ADB and angle ADB + angle BDA = 180 degrees, then angle BDA = 180 - 2 * angle ABD. 5. Plugging in the given values, we get angle BDA = 180 - 2 * 30 degrees = 120 degrees.
However, we know that triangle ABD is a 30-60-90 triangle, so angle ADB = 30 degrees.